MCNP6: error -- bad trouble in imcn is usually . . . - Physics Forums Hello, I'm new to MCNP deck-building, and I'm trying to acquire an X-ray energy spectrum using MCNP6, on Windows 10 environment I'm running MCNP6 via MCNPX Visual Editor Version X_24E, and the deck is input using built-in "Input File" tab in MCNPX Visual Editor My input deck is given below
Random Seed Choice for LAMMPS Molecular Dynamics Simulations The LAMMPS random number generator is a pseudo-random number generator (PRNG), meaning it can repeat sequences if the same seed is used For true randomness, it is recommended to use a source like random org for generating seeds
Will a Random Number Generator Eventually Repeat Its Numbers? Random number generators, as normally thought of, are programs on digital computers, where numbers have a finite number of bits Therefore there are only a finite number of possibilities for numbers out of the generator As a result, the generator must eventually repeat numbers it had turned out previously Then I suppose I do not think normally
Troubleshooting MCNP6: Bad Trouble in Subroutine Source More TL;DR Hi! so i kinda stuck when i tried to run my code in MCNP6 because the output keep showing me "bad trouble in subroutine source of mcrun you need a source subroutine " While im sure i already put my KCODE and KSRC in my code (on the picture below) Could anyone help me where i should start looking for the mistake? thank you!
Standard Deviation as Function of Sample Size • Physics Forums If is a random variable with standard deviation then taking 100 samples of does not change the standard deviation of , but the random variable defined by the mean of 100 samples of has a smaller standard deviation than Neither of these standard deviations is the same as an estimator of a standard deviation
How much money is needed to play this simple number game? The discussion revolves around a number guessing game where one player selects a number from 1 to 100, and the other guesses to win that amount The expected payout for the guessing player is derived from the probabilities of the chosen numbers, leading to the conclusion that the probability distribution should be proportional to 1 n