why is 00000000 - 00000001 = 11111111 in C unsigned char data type? I observed that, when a unsigned char variable stores the value 0 (00000000 2) and it gets decremented by 1 (00000001 2), the variable value turns into 255 (11111111 2), which is the highest value that a unsigned char variable can hold
How to represent 11111111 as a byte in java - Stack Overflow I know 11111111 could be an integer, but in my situation it must be represented as a byte because it must be sent to a file in byte form So how do I send a byte with the bits 11111111 to a file (by the way, this is my question)?
c# - Is it possible that GUIDs are generated with all the same . . . Kragen, I think you misunderstood my point It is next to impossible for any random GUID to be duplicated, so I was pointing out that there is no difference in probability (apart from the specific cases mentioned by Johannes) that two random generated GUIDs will match and a random guid and 11111111-1111-1111-1111-111111111111 will match
Why prefer twos complement over sign-and-magnitude for signed numbers? 11111111 (-1) +00000001 (1) you get 00000000 (0) The same is true for subtraction Also, if you try to subtract 4 from 6 (two positive numbers) you can 2's complement 4 and add the two together 6 + (-4) = 6 - 4 = 2 This means that subtraction and addition of both positive and negative numbers can all be done by the same circuit in the cpu
Chapter 4, Problem P5P - bartleby Textbook solution for Computer Networking: A Top-Down Approach (7th Edition)… 7th Edition James Kurose Chapter 4 Problem P5P We have step-by-step solutions for your textbooks written by Bartleby experts!