What is the difference between * arr and * arr[0] in C++, if arr is an . . . 1 Suppose I have an array of integers called arr I am trying to understand the distinction between * arr and * arr[0] I read that in C++, arr is essentially a pointer to the first element in the array and arr is a pointer to the whole array They both return the same address, I get this part
difference between using arr[i] and arr. length in the for loop . . . Using arr[i] as the continue condition checks the truthiness of the element at that position in the array This is a cute trick, but won't work if you want to iterate over arrays containing falsy values, like [1, 4, 6, 0, 3, 9] or [true, 'seven', false, -1, {foo: 'bar'}] Using i < arr length checks that the current index is less than the total length of the array
What is the meaning of arr [:] in assignment in numpy? Your question involves a mix of basic Python syntax, and numpy specific details In many ways it is the same for lists, but not exactly arr[:, 0] returns the 1st column of arr (a view), arr[:,0]=10 sets the values of that column to 10 arr[:] returns arr (alist[:] returns a copy of a list) arr[:]=arr2 performs an inplace replacement; changing the values of arr to the values of arr2 The
c - Difference between *arr [] and **arr - Stack Overflow Theoretically, *arr[] and **arr are different For example : char *arr[size]; case 1 Here arr is a an array of size size whose elements are of the type char* Whereas, char **arr; case2 Here arr is itself a pointer to the type char* Note: In case 1 array arr degrades to a pointer to become the type char** but it's not possible the other way around i e, pointer in case 2 cannot become an array
c - What is the difference between arr and *arr? - Stack Overflow Since arr[0] is an array, it is also converted to a pointer to its first element So the result is a pointer to arr[0][0] and that is what printf prints So, you are printing the address of arr[0] and the address of arr[0][0] Since they start in the same place, it is not surprising the address is the same
sorting - Selection Sort algorithm - Stack Overflow Selection Sort: I have created a selection sorting algorithm but someone said to me its not right selection sort If its not right so what type of sorting is it? and how it is different then sele
How *( arr + 1) - arr is working to give the array size The only difference is that the expression arr + 1 has the type int ( * )[7] while the expression arr + 7 has the type int * So due to the integer arithmetic the difference ( arr + 7 ) - arr will yield 7: the number of elements in the array