How do you explain the formula Fe3O4 using the ionic compound theory . . . So $\ce{Fe3O4}$ contains both Fe(II) and Fe(III) ions; twice as much Fe(III) as Fe(II) In the picture below, showing the crystal structure, green atoms are Fe(II) and brown atoms Fe(III) All Fe(III) atoms are linked with six O atoms, sharing 'half an electron' with each oxygen; all Fe(II) atoms are linked with four O atoms, and all O atoms
Why iron reacts with steam to give Fe3O4 not Fe2O3? Ma et al state, that crystalline $\ce{Fe3O4}$ (magnetite) is thermodynamically more stable than amorphous $\ce{Fe(OH)2}$ BTW, the stability of magnetite, and its adherence to iron, is used to protect steel from rusting "Blueing creates a layer of magnetite over the metal to prevent rust " See also this question
Fe3O4 as a mixed oxide - Chemistry Stack Exchange Iron(II,III) oxide $\ce{Fe3O4}$: has a cubic inverse spinel group structure which consists of a cubic close packed array of oxide ions where all of the $\ce{Fe^2+}$ ions occupy half of the octahedral sites and the $\ce{Fe^3+}$ are split evenly across the remaining octahedral sites and the tetrahedral sites
How is the triferric tetroxide of iron possible? In regards to $\ce{Fe3O4}$, according to the Wikipedia page Iron(II,III) oxide, contains both $\ce{Fe^2+}$ and $\ce{Fe^3+}$ ions A 2-dimensional diagram of $\ce{Fe3O4}$ is below, from the relevant ChemSpider page: A 3-dimensional model is below (from Wikipedia): red indicate oxygen
Why is Fe3O4 a non-stoichiometric compound? [closed] The fact a compound has mixed oxidation numbers like $\ce{Fe3O4}=\ce{Fe^{II}Fe^{III}2O4}$ or $\ce{Pb3O4}=\ce{Pb2^{II}[Pb^{IV}O4]}$, so it cannot be expressed by a single integer oxidation number, does not alone make the compound non-stoichiometric But deviations in composition, leading to rational atom ratios, do make such a compound non
Solved 3. Magnetite, Fe3O4, (Molar Mass = 232 g. moll) can be - Chegg Magnetite, Fe3O4, (Molar Mass = 232 g moll) can be reduced to iron (Fe, Awt = 56 g mol by heating Fe3O4 with carbon monoxide according to the equation: Fe3O4(s) + 4CO(g) → 3Fe (s) + 4CO2(g) What mass of Fe3O4 is required in order to obtain 5 0 kg of iron if the process is 88% efficien a 6 1 kg b 6 9 kg c 18 kg d 7 8 kg e 15 8 kg
Reaction of iron with steam - Chemistry Stack Exchange Actually, Fe3O4 has a crystal structure (an extended geometrically regular array) of Fe(III), Fe(II) and oxide ions in which the oxide ions exist in a cubic close packed pattern with the Fe(II) ions located at half of the octahedral sites and the Fe(III) ions distributed evenly between octrahedral and tetrahedral sites $\endgroup$
Solved EXERCISES An ore containing magnetite, Fe3O4, was - Chegg EXERCISES An ore containing magnetite, Fe3O4, was analyzed by dissolving a 1 5419-g sample in concentrated HCl, giving a mixture of Fe2+ and Fe3+ After adding HNO3 to oxidize any Fe2+ to Fe3+, the resulting solution was diluted with water and the Fe3+ precipitated as Fe(OH)3 by adding NH3
Solved Given the following equation: 3 Fe + 4 H2O → Fe3O4 - Chegg Given the following equation: 3 Fe + 4 H2O → Fe3O4 + 4 H2 What is the mass of Fe3O4 that can be produced when 4 7 g of Fe react with 7 4 g of H2O? Your solution’s ready to go! Our expert help has broken down your problem into an easy-to-learn solution you can count on