MOSFET Power Supply Explained - Electrical Engineering Stack Exchange By my understating the MOSFET only amplifies current, not voltage, so how is the output changing with the jumpers? Edit: I understand now that the transistors are working as an amplifier to give a negative voltage potential to the FET I am now struggling to grasp how the current changing from the FET changes the output voltage
What is the difference between MOSFET transistor and normal transistor . . . 16 [From Question]: MOSFET transistor and normal transistor A MOSFET is a normal transistor - it's a Metal-Oxide-Semiconductor Field-Effect Transistor A BJT is another normal transistor - a Bipolar Junction Transistor The question itself doesn't make much sense in that regard But lets assume for now you mean BJT when you say "normal"
mosfet - Why does current mirror need a diode connected configuration . . . The equations work both ways For a BJT, the Shockley equation relates collector current to base-emitter voltage You can supply the collector current and get an emitter-base voltage Wiring it up as a diode arranges things so that the current flooding the device will be only partially diverted to the base, with most of it as collector current But the base-emitter voltage (with collector
mosfet - How can I do a heatsink calculation and determine whether a . . . I am designing a DC solid-state relay using an FQP30N06L (a MOSFET with 32 A, 60 V, R ds (on) = 0 035 Ω @V gs = 10 V) to control using a Raspberry Pi I am trying to control an electric door lock with 6-12 V 1200 mA; the nominal resistance at 12 V is 9 Ω
mosfet - How to do high voltage high-side switching in a simple and . . . It appears they also wear out much quicker And solid state relays that I have found so far are generally very large compared to a mosfet or relay and drop a constant voltage up to 1V across them, which would be a big problem for high side switching of say 5V