A chemist heats 100. 0 g of FeSO_4 * 7H_2O n a crucible to . . . - Socratic 54 64 "g" anhydrate With "100 0 g" of the heptahydrate, use the molar mass to determine how many mols you have Mols are interconvertible, as one mol of anything is the same number of particles as one mol of anything else 100 0 cancel("g FeSO"_4cdot7"H"_2"O") xx ("1 mol FeSO"_4cdot7"H"_2"O") (278 02 cancel("g FeSO"_4cdot7"H"_2"O")) = "0 3597 mols" For each "mol" of the heptahydrate, you have