Expected number of ratio of girls vs boys birth NumberOfChilden Probability Girls Boys 1 0 5 1 0 2 0 25 1 1 2 0 25 0 2 In this case the total expected children is more easily calculated Expected girls from one couple${}=0 5\cdot1 + 0 25\cdot1 =0 75$
probability - What is the expected number of children until having at . . . $\begingroup$ That can't be right, and you can see that by noting that the MINIMUM number of children is 2 If the expected number of children = the minimum number of children, it must be that there is no possibility of having more children than the minimum number - otherwise the expected number of children would be greater than the minimum number
combinatorics - All combinations for a King and Queen (coed) 2s . . . Ok so I have N girls and N guys I need to create a 2's beach volleyball coed tournament (also known as King and Queen style) I want a list (like Joe and Jill versus Donald and Melania etc ) of all possible unique games, given the following constraints: Coed 2's, so 2 members per team, 1 girl and 1 guy
How to resolve the ambiguity in the Boy or Girl paradox? The net effect is that even if I don't know which one is definitely a boy, the other child can only be a girl or a boy and that is always and only a 1 2 probability (ignoring any biological weighting that girls may represent 51% of births or whatever the reality is)
probability - What is the expected number of children until having the . . . You can consider starting from position 1 for the difference of boys girls and move up and down randomly with 50% probability until reaching zero These type of walks have been described here: What is the distribution of time's to ruin in the gambler's ruin problem (random walk)? and based on the results in those answers we can see that the
Combinatorics - Arranging boys girls - Cross Validated part (b) - the chances of a girls stand next to a boy is 1 the chances of a boy to stand next to a girl is 1 minus the chance not to stand next to a girl the answer is 1 - (answer from part 1) : 1 - 3 10 = 7 10 not sure this is the correct answer Thanks in advance for the help
Hypothesis testing: Fishers exact test and Binomial test The result obtained with the Fisher's exact test ("no significant difference between the proportion of girls and boys who finds that the cake tastes good") seems to contradict the results in (1) and (2), which say that the "more than 50% of the population of girls find that the cake tastes good" (1), and "no more than 50% of boys find that the
Probability of having a sister - Cross Validated For families with 2 girls (0 25 probability), the random girl has a sister For families with 3 or more girls (0 15 + 0 1 probability), the random girl also has a sister Add up these probabilities: 0 25 + 0 15 + 0 1 = 0 5 So, the probability that a random girl has a sister is 0 5 or 50% "
Learning probability bad reasoning. Conditional and unconditional . . . (Source: Minka ) My neighbor has two children Assuming that the gender of a child is like a coin flip, it is most likely, a priori, that my neighbor has one boy and one girl, with probability 1 2 The other possibilities—two boys or two girls—have probabilities 1 4 and 1 4 a Suppose I ask him whether he has any boys, and he says yes