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- Solve (sec^{2}27^{circ}-cot^{2}63^{circ})+(sin^252^circ+sin^238^circ . . .
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- [Solved] The value of \ (\frac { {2 { {\sin }^2}38^\circ { {\sec }^2}5
sec 2 θ - tan 2 θ = 1 Calculation: \(\frac{{2{{\sin }^2}38^\circ {{\sec }^2}52^\circ + \rm cos64^\circ \;sin26^\circ + {{\sin }^2}64^\circ }}{{{{\tan }^2}23^\circ + {{\cot }^2}23^\circ - {{\sec }^2}67^\circ - \rm cose{c^2}67^\circ }}\)
- cos^2 27° - sin^2 63° - Sarthaks eConnect
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- Solve frac{(sec^{2}27^{circ}-cot^{2}63^{circ})+(sin^{2}52^{circ}+sin^{2 . . .
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