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- 2 Evaluate the greatest pressure of water in | StudyX
The water in the tank is pressurised by the air and the pressure is measured by the multifluid manometer as shown Determine the absolute pressure of air in the tank (in kPa ) if h1=26 m h2=12 m h3=15 m Take the densities of water oil and mercury to be 1000 kg m3 850 kg m3 13600 kg m3 respectively The local atmospheric pressure is 1002 kPa
- 2 Evaluate the greatest pressure of water in the tank shown Diagram . . .
Similar Questions The closed tank of in following figure is filled with water and is 15-m long The pressuregage on the tank reads 50 kPa (gage pressure) Determine(a) the height h in the openwater column (b)the gage pressure acng on the botom tank surface AB and (c)theabsolute pressure of the air in the top of the tank if the local atmospheric pressure is 1013kPa Assume water density is 1000
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- 4 Evaluate the greatest pressyre of water | StudyX
Click here 👆 to get an answer to your question ️ 4 Evaluate the greatest pressyre of water in the tank shown Homework Help Math Solver; Math AI; AI Tutor; Ask AI Questions; AI Answer Generator; Code Generator; All Study tools; AI Note AI PDF Summarizer; AI PowerPoint Summarizer; AI Lecture Note Evaluate the greatest pressyre of
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- As shown in the figure compute the pressure | StudyX
Step 1: Calculate the pressure at point C due to water The depth of point C below the water surface is 1 m Assuming the density of water is 1000 kg m³ and g = 9 81 m s², the pressure at C due to water is: P water = ρ water gh water = (1000 kg m³)(9 81 m s²)(1 m) = 9810 Pa Step 2: Calculate the pressure at point C due to oil
- An open tank contains 5m deep of liquid having a unit weight of 7kN m3 . . .
Step 1: Calculate Pressure Due to the First Liquid Pressure P₁ = depth × unit weight = 5 m × 7 kN m³ = 35 kPa Step 2: Calculate Pressure Due to Water Depth of water = 8 m - 5 m = 3 m Pressure P₂ = 3 m × 9 81 kN m³ = 29 43 kPa Step 3: Calculate Total Gage Pressure Total pressure P total = P₁ + P₂ = 35 kPa + 29 43 kPa = 64 43
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