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- F (x)=6x-9 L=-3 c=1 ε=0. 01 find the δ gt;0 help me to get the . . . - Socratic
We know the following #epsilon-delta# Definition of Limit : #AA epsilon > 0, EE" a "delta > 0," such that, "#
- Question #7dc79 - Socratic
We have #f (x,y)=xy^2# and we want to use linear approximation to estimate #f (2 01,3 02)#
- Question #b5e69 - Socratic
3 01 xx 10^21" molecules O"_2 M_ (CO_2) = "220 mg" MW_ (CO_2) = "44 01 g mol" "O"_2 " molecules = ?" "moles " CO_2 = (M_ (CO_2)) (MW_ (CO_2)) = ("220 mg" "1000 mg g
- Question #6f7d1 - Socratic
675N Here,the kinetic energy of the hammer head got totally converted to the work done in moving the nail through a distance of 10 mm or 0 01 m So, kinetic energy of the hammer during the strike was 1 2 m v^2=1 2×1 5×3^2=6 75J Now,if an average force of F had acted on the nail to move it by 0 01 m,then work done by the force will be (F×0 01)J(using W=F*s) So,we can equate both 6 75=F×0 01
- Question #fe281 - Socratic
4 ⋅ 12 01 = 48 04 g We now know that one mole of carbon contains 48 04 grams of carbon Next, we determine how many grams of carbon are in one mole of CO 1 ⋅ 12 01 = 12 01 g Now, we know that one mole of CO contains 12 01 grams of carbon With this information, we can determine how many moles of CO can be formed with the given mass of C
- Question #914ef - Socratic
The molecular formula is "C"_4"H"_8"O"_2 > (a) Calculate the mass of "C" "Mass of C" = 8 45 color (red) (cancel (color (black) ("mg CO"_2))) × "12 01 mg C" (44 01
- Question #315e6 - Socratic
14 33"g of "H_2O Here is your balanced equation: C_6H_12O_6+ 6O_2rarr 6H_2O+6C0_2 We start Dimensional analysis (the factor-label method) by writing the given information over 1: (35"g of "CO_2) 1 We look up the molar mass of CO_2 and multiply by that factor so that it converts the units to moles: (35"g of "CO_2) 1(1"mol of "CO_2) (44 01"g of "CO_2) Please observe how the units cancel and we
- Question #8b670 - Socratic
The reaction produces 20 g of "NO" > We are given the amounts of two reactants, so this is a limiting reactant problem We know that we will need a balanced equation with masses, moles, and molar masses of the compounds involved Step 1 Gather all the information in one place with molar masses above the formulas and everything else below the formulas M_r:color(white)(mmmmll) 17 03color
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