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- Creating arithmetic expression equal to 1000 using exactly eight 8s . . .
I would like to find all the expressions that can be created using nothing but arithmetic operators, exactly eight $8$'s, and parentheses Here are the seven solutions I've found (on the Internet)
- Exactly $1000$ perfect squares between two consecutive cubes
Therefore there are exactly $1000$ squares between the successive cubes $ (667^2)^3$ and $ (667^2+1)^3$, or between $444889^3$ and $444890^3$ Finally, we can verify all of this by using the command line utility bc: $ bc sqrt((667^2)^3) 296740963 sqrt((667^2+1)^3-1) 296741963 Cite edited Nov 27, 2025 at 22:11 community wiki 5 revs R P A
- combinatorics - How many numbers are there between 99 and 1000, having . . .
First of all, from 99 to 1000, we have 100 to 999, meaning $9*10*10$ since 1 to 9 is 9 numbers We have 900 numbers Then, to get all numbers with at least one $7$ in their digits, we can do: All
- Why is kg m³ to g cm³1 to 1000? - Mathematics Stack Exchange
I understand that changing the divisor multiplies the result by that, but why doesn't changing the numerator cancel that out? I found out somewhere else since posting, is there a way to delete this?
- probability - 1 1000 chance of a reaction. If you do the action 1000 . . .
A hypothetical example: You have a 1 1000 chance of being hit by a bus when crossing the street However, if you perform the action of crossing the street 1000 times, then your chance of being
- combinatorics - The number of bacteria in a culture is 1000 and this . . .
The number of bacteria in a culture is 1000 and this number increases by 250% every two hours How many bacteria is present after 24 hours?
- algebra precalculus - Multiple-choice: sum of primes below $1000 . . .
Given that there are $168$ primes below $1000$ Then the sum of all primes below 1000 is (a) $11555$ (b) $76127$ (c) $57298$ (d) $81722$ My attempt to solve it: We know that below $1000$ there are $167$ odd primes and 1 even prime (2), so the sum has to be odd, leaving only the first two numbers
- elementary probability - What is the chance that a 1 in 1000 event will . . .
A big part of this problem is that the "1 in 1000" event can happen multiple times within our attempt Compare this to if you have a special deck of playing cards with 1000 cards in it, exactly one of those cards is the ace of spades
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