安裝中文字典英文字典辭典工具!
安裝中文字典英文字典辭典工具!
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- Find the zeroes of the polynomial in g (x)= 3-6x - Socratic
x = 1 2 A theorem states that every polynomial of degree n as exactly n solutions in the complex field If you don't know what complex numbers are, you just have to know that, if you use real numbers, you will find no more than n solutions for a polynomial of degree n In this case, we have a polynomial of degree 1, so it can only have one solution To find it, we need to find a value for x
- How do you complete the square for : x^2 + 6x? | Socratic
So #x^2 +6x = (x+3)^2 - 9# If you were actually trying to solve #x^2+6x=0#, then completing the square would be a round about way of doing it, but would look something like this:
- How do you solve the differential equation given g (x)=6x^2 . . . - Socratic
Explanation: # g' (x) = 6x^2 # So we can integrate to get; # g (x) = int 6x^2 dx# # : g (x) = 2x^3 + C #
- How do you solve and write the following in interval notation: x^2 + 6x . . .
The interval notation is ] -oo,-5 ] uu [-1,+oo [ Let's factorise the equation y=x^2+6x+5>=0 => (x+1) (x+5)>=0 Let's do a sign chart color (white) (aaaa)xcolor (white
- What is the factorization of #x^2+6x+9#? - Socratic
The factored version is (x+3)^2 Here's how I approached it: I can see that x is in the first two terms of the quadratic, so when I factor it down it looks like: (x+a)(x+b) And when that gets expanded it looks like: x^2+(a+b)x+ab I then looked at the system of equations: a+b=6 ab=9 What caught my eye was that both 6 and 9 are multiples of 3 If you replace a or b with 3, you get the following
- How do you solve #2 ( x - 8) + 9x - 8= 6x - 24#? - Socratic
x = 0 First, expand the term in parenthesis: 2x - 16 + 9x - 8 = 6x - 24 Next, combine like terms: 11x - 24 = 6x - 24 Finally solve for x while keeping the equation balanced: 11x - 24 - + 24 - 6x = 6x - 24 + 24 - 6x 5x = 0 (5x) 5 = 0 5 x = 0
- How do you solve the quadratic equation by completing the square: x^2 . . .
Explanation: In order to solve this quadratic equation by completing the square, you need to write the left side of the equation as the square of a binomial
- How do you use the important points to sketch the graph of y=x^2+6x+5 . . .
The curve is above this vertex and is symmetrical about its axis #x=-3# This is parallel to y-axis Put y= o and solve #x^2+6x+5=0#
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