casting - Converting double to integer in Java - Stack Overflow is there a possibility that casting a double created via Math round() will still result in a truncated down number No, round() will always round your double to the correct value, and then, it will be cast to an long which will truncate any decimal places But after rounding, there will not be any fractional parts remaining Here are the docs from Math round(double): Returns the closest long to
Casting to void* and Back to Original_Data_Type* Casting to void* removes all type safety If you use reinterpret_cast or static_cast to cast from a pointer type to void* and back to the same pointer type, you are actually guaranteed by the standard that the result will be well-defined
casting - C convert floating point to int - Stack Overflow I don't understand what you mean by “convert an int to a binary number”— int already is binary… Or do you mean to convert it to a string of the binary representation, e g convert 14 to "1110" Either way: How did the floating point numbers get into that conversion?
c++ - What does casting to `void` really do? - Stack Overflow Casting a variable expression to void to suppress this warning has become an idiom in the C and later C++ community instead because the result cannot be used in any way (other than e g (int)x), so it's unlikely that the corresponding code is just missing
java: How can I do dynamic casting of a variable from one type to . . . 2 Your problem is not the lack of "dynamic casting" Casting Integer to Double isn't possible at all You seem to want to give Java an object of one type, a field of a possibly incompatible type, and have it somehow automatically figure out how to convert between the types