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- c++ - What does initialization exactly mean? - Stack Overflow
In practice, constant initialization is usually performed at compile time, and pre-calculated object representations are stored as part of the program image If the compiler doesn't do that, it still has to guarantee that this initialization happens before any dynamic initialization
- What distinguishes the declaration, the definition and the . . .
Initialization includes things like the zero initialization of variables with static lifetime, and default constructors, as well as what you show (And to add to the confusion: in C, initialization can be the first time the variable is assigned to; e g in statements like "taking the value of an uninitialized variable"
- What is the difference between initialization and assignment?
Yet, at the C++ technical level initialization has already been done, by a call of std::string's default constructor, so at this level one thinks of the declaration as initialization, and the assignment as just a later change of value So, especially the term "initialization" depends on the context!
- Java: define terms initialization, declaration and assignment
Initialization: Initialization is when we put a value in a variable, this happens while we declare a variable Example: int x = 7;, String myName = "Emi";, Boolean myCondition = false; Assignment: Assignment is when we already declared or initialized a variable, and we are changing the value You can change value of the variable as many time
- What is the difference between instantiated and initialized?
Here are examples of initialization: obj = 1 obj = "foo" Instantiation is a very different thing but is related since instantiation is usually followed by initialization: Dim obj As New Object() In the preceding line of code, the obj variable is initialized with the reference to the new Object that was instantiated
- Declaring vs Initializing a variable? - Stack Overflow
Not exactly 'Initialization' is something that happens during runtime when the engine is preparing everything During initialization, an initial value of undefined gets assigned The second example in your answer is actually 'assignment' as you stated, but as a variable can have a new value assigned to it multiple times, it's important to note
- initialization - How to initialise memory with new operator in C++ . . .
Note that you must use the empty parentheses — you cannot, for example, use (0) or anything else (which is why this is only useful for value initialization) This is explicitly permitted by ISO C++03 5 3 4[expr new] 15, which says: A new-expression that creates an object of type T initializes that object as follows:
- Initialization vs Assignment in C - Stack Overflow
Using "initialization" to refer to both cases is confusing because there is a very important distinction What you refer to as the "first way" is usually called "static initialization" When you write "static int x[2]={1,2}", the compiler will generate a data block containing the values "1, 2" and then initialize X to point to the memory
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