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- How many orbitals are described by each of the below . . . - Wyzant
n = 3, l = 2 describes 5 orbitals since l = 2 denotes d orbitals and there are 5 of them n = 4, l = 2, ml = 2 describes 1 orbital since l = 2 denotes d orbitals, of which there are 5, but the ml = 2 defines the particular d orbital in question
- usr bin ld: cannot find -l lt;nameOfTheLibrary gt;? - Wyzant
In the case of the second, where you know the library is installed, you just need to find it Once you have the path to the so file, add a -L flag to your g++ command and give it the path to the directory containing your so file The -L flag tells g++ to have the linker search the additional location for shared object files
- Reaction between sodium thiosulfate and hydrochloric acid?
Na 2 S 2 O 3 (aq) + 2HCl (aq) ==> SO 2 (aq) + S(s) + H 2 O(l) + 2NaCl (aq) balanced equation Not sure how detailed of an explanation you need want, but you can see from the balanced equation that when sodium thiosulfate (a colorless solution) is combined with aqueous HCl (a colorless solution), one of the products is SOLID sulfur
- Titrations and Buffers | Wyzant Ask An Expert
What is the pH of a 1 0 L buffer made with 0 300 mol of HF (Ka = 6 8 × 10⁻⁴) and 0 200 mol of NaF to which 0 100 mol of HCl were added?
- Solved Calculate the standard entropy, Δ𝑆∘rxn, of the - Chegg
C2H4(g)+H2O(l) C2H5OH(l) Calculate the standard Gibbs free energy of the reaction, Δ𝐺∘rxn The standard enthalpy of the reaction, Δ𝐻∘rxn, is −44 2 kJ⋅mol−1 Determine in which direction the reaction is spontaneous as written at 25 0 ∘C25 0 ∘C and standard pressure 1 neither 2 reverse 3 forward 4 both
- Solved The rigid bar AC has length L = 1075 mm and is - Chegg
Question: The rigid bar AC has length L = 1075 mm and is supported by a pin at A and is pin-connected to the deformable rod BD at B The deformable rod BD has a length b = 674 mm, elastic modulus E = 200 GPa, and a circular cross-section with a diameter of d = 19 mm Consider a = 695 mm and =31 TL b A B L Matlab Mathematica Python R Sympy L
- Given: m∠A=100°, m∠L=25°,OA = 21 Find: AK, AL, KL
Connect the point "O" with point "L" ΔAOL is the isosceles triangle with AO = LO = 12 ∠AOL is a central angle ∠AKL is an inscribed angle, intersecting the same ark of the circle m∠AOL = 2(m∠AKL) = 2 • 55° = 110° To find AL, we will use the Law of Cosines: AL = √(12 2 + 12 2 - 2•12 2 •cos(110°) ≅ 19 659649 Calculating AK
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