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- Is a DFA a subset of NFA? Why? - Mathematics Stack Exchange
Yes every NFA has a corresponding DFA, the process of constructing the DFA from the NFA is called subset construction In essence each state of the DFA is a set of states of the NFA The constructed DFA recognizes the same formal languange as the starting NFA
- Convert from DFA to NFA - Mathematics Stack Exchange
For this language $\{ w \mid w \text{ contains at least three 1's} \}$, its DFA diagram is defined as follows: While trying to convert it to NFA, but I realized that its NFA would be identical to its DFA I'm not sure is it possible or not since I know there is a procedure to convert from NFA to DFA
- formal languages - how to reduce DFA to NFA with less states . . .
Given DFA Convert this DFA to NFA with 5 states DFA IMAGE ATTACHED I plan is to find a language and regular expression first and then try to convert regular expression to NFA with 5 states But I had hard time just to find the language it accepts How to approach these problems And to how to find language or regular expressions for large DFA's?
- Automaton NFA that include substring aa and bb
Please see whether the below DFA (which is of course also an NFA) works? Description: S is the starting state and AABB is the terminal state, which is also an accepting state $\{A, B,AA,BB,AAB,BBA\}$ are all intermediary states
- Proving Equivalence of DFA and NFA - Mathematics Stack Exchange
$\begingroup$ Thanks for the answer :) Yeah i mean Σ I Understand that The difference between NFA and DFA is the presense absense of more than one transition on the same input symbol As you have mentioned for NFA -> Q×Σ to 2^Q But in the above example you can see that it is given as M' is the DFA and Q'is associated with the DFA not the NFA is this a mistake in the textbook $\endgroup$
- If every NFA is a DFA, the fact that I can make an NFA to a single . . .
First, it’s not true that every NFA is a DFA: exactly the opposite is true (Judging by your question, this might even have been what you were actually thinking ) What you’ve already proved therefore shows that every DFA can be converted to an NFA with a single acceptor state, but it doesn’t prove that every DFA can be converted to a DFA
- computer science - Im trying to convert an NFA to a DFA and I am . . .
As to this problem, first you need to convert your NFA+ $\epsilon$ to an equivalent NFA without $\epsilon$ transitions Then, you can use the state-subsets construction to convert it to DFA If you just want a hint: to convert your NFA+ $\epsilon$ to an equivalent NFA without $\epsilon$ transitions, you need to use the concept of $\epsilon
- How to convert Finite Automaton (FA) to Non-Deterministic FA (NFA) with . . .
Find an NFA (non-deterministic FA) with four states that accepts the same language The question paper came with a memo and the following is the answer: I tried to find some tutorials on YouTube to explain how this conversion is done but all I could find is NFA to DFA and minimizing DFA (but here the FA must first be converted to DFA)
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