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- Question #87b82 - Socratic
See a solution process below: First, we need to determine how much was left before the man spent 20% We can rewrite this part of the problem as: 10200 is 80% of what? We are using 80% because he spent 20% so the man has 100% - 20% = 80% left "Percent" or "%" means "out of 100" or "per 100", Therefore 80% can be written as 80 100 When dealing with percents the word "of" means "times" or "to
- Question #b4092 | Socratic
Two main tendencies are part of the Republican Party: the Old Right and the New Right The Old Right or Paleo-Conservatives are Constitutionalists, they reject any form of Welfare state and military interentions abroad unlike the NeoConservatives who favor state intervention in the economy and the policeman of the world role for the USA
- Question #cebdb - Socratic
The resultant vector shows the plane moving 528 16 kph bearing 65 9 degrees I always like to sketch out an idea of what we're looking at Let's resolve the vectors and find the x and y components * * * * * * * * * * * * * * * * * * * * * * * Vector A 500 kph 60 degrees We can find the y component using sin (theta)= (opp) (hyp) Lucky for us, we have hyp, 500, and theta, 60 sin (60)= (opp) 500
- Answers created by James - Socratic
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- How to solve the problem?? - Socratic
#If,cscA+cscB+cscC=0 #,then show that # (sumsinA)^2=sumsin^2A# Trigonometry
- Question #6fb9d - Socratic
sf ( ("d"theta) dt=- 0 02color (white) (x)" rad s") In degrees: sf ( ("d"theta) dt=-1 15^@" s") We are told: sf ( (dX) dt=8color (white) (x)"ft s") We need to find sf
- Question #b56ad - Socratic
Explanation: Velocity of man just prior to landing on the pad #=4 4ms^-1# Momentum of man just prior to landing on the pad #p=mv# #=50xx4 4=220kgms^-1# Final velocity #=0# Change of momentum of man on his landing on the pad #=0-220=-220# From Newton's Second law of motion we know that Rate of change of momentum is the force applied #=-220 0 2
- How do you add 2sqrt75+sqrt108-2sqrt75? | Socratic
1 Answer ali ergin Aug 11, 2016 #2sqrt 75+sqrt 108-2 sqrt 75=6sqrt3#
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