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- Question #8556c - Socratic
This means that the anilinium ion is a reasonably strong conjugate acid producing higher degree of hydrolytic effect than the Nitrite ion which => # [H^+] > [OH^-]# => pH < 7 (acidic)
- What is the product of the following reaction? 1)CH_3 OH - Socratic
These are ostensibly acid-base reactions For ammonium we could write NH_4^+ +HO^(-) rarr NH_3(aq) + H_2O(l) For methanol, the acid base reaction would proceed
- Question #c8170 - Socratic
Zn(OH)_2 + 2HCl to ZnCl_2 + 2H_2O The basic equation is: Zn(OH)_2 + HCl to ZnCl_2 + H_2O if we balance the Chlorine atoms Zn(OH)_2 + 2HCl to ZnCl_2 + H_2O We now have to balance the oxygen atoms Zn(OH)_2 + 2HCl to ZnCl_2 + 2H_2O We now have the same number of each atoms of each element on each side of the equation
- How is the pH of a solution related to the [H_3O^+]? | Socratic
pH=-log_10 [H_3O^+] So given a neutral solution, [H_3O^+] [HO^-]=10^ (-14), and since, by definition, [H_3O^+]= [""^ (-)OH], i,e, [H_3O^+] = 10^-7*mol*L^-1 And thus
- Question #f2dad - Socratic
1 The yield will decrease; 2 There will be no effect on the yield > 1 Using 80 % propan-1-ol I'm guessing that you are making the propyl ester of a carboxylic acid and then titrating the reaction mixture to determine how much acid remains at the end of the esterification underbrace ("RCOOH")_color (red) ("carboxylic acid") + underbrace ("CH"_3"CH"_2"CH"_2"OH")_color (red) ("propan-1-ol
- Question #cebdb - Socratic
The resultant vector shows the plane moving 528 16 kph bearing 65 9 degrees I always like to sketch out an idea of what we're looking at Let's resolve the vectors and find the x and y components * * * * * * * * * * * * * * * * * * * * * * * Vector A 500 kph 60 degrees We can find the y component using sin (theta)= (opp) (hyp) Lucky for us, we have hyp, 500, and theta, 60 sin (60)= (opp) 500
- Question #ccabf - Socratic
Because N aOH → N a+ + OH − and N i2+ + 2OH −→N i(OH)2 Total Mols of N aOH: 60mL ⋅ 0 45M ol L = 27mM ol of N aOH (dont forget the m for milli=one thousandth) This will produce 27 2 = 13 5mM ol of N i(OH)2 Now you multiply this by the molecular mass number to get the weight in milligrams (divide by 1000 to get the grams) Nickel (II)hydroxide may be formed without or (more likely
- Question #22e51 - Socratic
Products formed are; Cu (OH)_2 + HCl -> CuCl_2 + H_2O Since CuCl_2 is soluble in water But; Cu (OH)_2 + HCl -> CuCl_2 + H_2O " [Not Balanced]" Balancing the equation
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