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- Question #845d9 + Example - Socratic
The inductive effect is the effect on electron density in one portion of a molecule caused by electron-withdrawing or electron-donating groups elsewhere in the molecule In a covalent bond between two atoms of unequal electronegativity, the more electronegative atom draws electron density towards itself This causes the δ⁺ and δ⁻ charges of the bond dipole "H"^(δ+)-"Cl"^(δ-) If the
- Question #c548d - Socratic
Question 1: K_ (sp)= 1 1 xx10^ (-11) Question 2: s= 4 9 xx10^ (-12)M Quest (1) determine the ksp for magnesium hydroxide Mg (OH)_2 where the molar solubility of Mg
- Question #e7848 - Socratic
Similarly, OH^- becomes H_2O, indicating a gain of a H^+ ion So, you can say that NH_4^+ is the acid, and OH^- is the base Conjugates are basically the "other" term For every acid, you have a conjugate base (that no longer has that extra H^+ ion), and for every base, you have a conjugate acid (that has an extra H^+ ion)
- Calculating the concentration of excess HCL in E - Socratic
The acid in excess is then titrated with N aOH (aq) of KNOWN concentration we can thus get back to the concentration or molar quantity of M (OH)2 as it stands the question (and answer) are hypothetical
- Question #a87b0 - Socratic
Strong Base collection => Group IA and Group IIA Hydroxides (Except for Beryllium Hydroxide) can be titrated with strong acid such that concentration of Alkali-Hydroxide = concentration of Hydroxide ion in solution indicates 100% dissociation Starting with say 1 0 mole Liter NaOH in aqueous solution and titrating to end point with strong acid ( ~HCl(aq)) gives concentration of the Hydroxide
- Question #889ec - Socratic
Explanation: < Since the molarity of either acid is the same, the moles of each acid are equal That means the difference between their pH is determined solely on which acid dissociates more Since the strong acid dissociates more (releases more #H^+# ions), it will have a lower pH = Since both acids are monoprotic (they only release one hydrogen) they will both take the same amount of #OH
- Question #99a62 - Socratic
The sulfate (VI) ion SO_4^(2-) is the only spectator in this reaction The solubility of cobalt (III) hydroxide is only about 10^(-10) g l so can be considered to be insoluble We need a balanced equation so the essential reaction that is happening here is that between acid and base : H_"(aq)"^++OH_"(s)"^-rarrH_2O_"(l)" We can see that the 3 hydroxide ions in cobalt (III) hydroxide will need 3
- Question #97503 - Socratic
Here's what I get The general equation for the dissociation of a carboxylic acid is "R-COOH + H"_2"O" ⇌ "R-COO"^"-" + "H"_3"O"^+ All we have to do is write the
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