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  • How is the pH of a solution related to the [H_3O^+]? | Socratic
    pH=-log_10 [H_3O^+] So given a neutral solution, [H_3O^+] [HO^-]=10^ (-14), and since, by definition, [H_3O^+]= [""^ (-)OH], i,e, [H_3O^+] = 10^-7*mol*L^-1 And thus
  • What is the product of the following reaction? 1)CH_3 OH - Socratic
    These are ostensibly acid-base reactions For ammonium we could write NH_4^+ +HO^(-) rarr NH_3(aq) + H_2O(l) For methanol, the acid base reaction would proceed
  • Question #8556c - Socratic
    This means that the anilinium ion is a reasonably strong conjugate acid producing higher degree of hydrolytic effect than the Nitrite ion which => # [H^+] > [OH^-]# => pH < 7 (acidic)
  • Question #cb195 - Socratic
    Basic [H_3O^+]= [OH^-]=10^ {-7} M is a neutral solution With higher [H_3O^+] you have [OH^-] and an acidic solution With lower [H_3O^+] you get higher [OH^-] and you have a basic solution
  • Question #c8170 - Socratic
    Zn(OH)_2 + 2HCl to ZnCl_2 + 2H_2O The basic equation is: Zn(OH)_2 + HCl to ZnCl_2 + H_2O if we balance the Chlorine atoms Zn(OH)_2 + 2HCl to ZnCl_2 + H_2O We now have to balance the oxygen atoms Zn(OH)_2 + 2HCl to ZnCl_2 + 2H_2O We now have the same number of each atoms of each element on each side of the equation
  • Question #c76b8 - Socratic
    Answer below Calcium oxide will dissolve to produce Calcium Hydroxide It is as follows: CaO + H_2O to Ca (OH)_2 In essence: "base + water" to "alkali"
  • Question #c2681 - Socratic
    The pH of the solution is 5 97 > The "NaOH" reacts with the "H"_2"PO"_4^"-" 0 460 color (red) (cancel (color (black) ("g NaOH"))) × "1 mol NaOH" (40 00 color (red
  • Question #627ef - Socratic
    functional groups like -OH, -CHO,-CO- are present in carbohydrates commonly two functional are present in a carbohydrate,-OH and -CHO, or -OH and-CO- Aldose shows different reactions and test like Tollen's silver mirror test, felling's test different types of reactions are also shown by carbohydrates like Osazone synthesis, length increasing reaction, oxidation reactions These are all due


















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