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- Question #6f366 - Socratic
Here's what I get > The reaction is a simple proton transfer from the acid to the amine to form an ammonium salt The equation for the salt formation is underbrace
- Question #851e9 + Example - Socratic
The equation for this is: H^+ (aq)+OH^ (-) (aq)rightleftharpoonsH_2O (l) A common example of a neutralization reaction would be adding hydrochloric acid to aqueous sodium hydroxide
- Question #f2dad - Socratic
1 The yield will decrease; 2 There will be no effect on the yield > 1 Using 80 % propan-1-ol I'm guessing that you are making the propyl ester of a carboxylic acid and then titrating the reaction mixture to determine how much acid remains at the end of the esterification underbrace ("RCOOH")_color (red) ("carboxylic acid") + underbrace ("CH"_3"CH"_2"CH"_2"OH")_color (red) ("propan-1-ol
- Question #bb4d7 - Socratic
Since there are both H^+ and OH^- ions in water, bicarbonate ions get hydrated really quickly to form carbonic acid, and the equation is HCO_3^ (-)+H^+rightleftharpoonsH_2CO_3 Know that, carbonic acid is a weak acid This leaves OH^- in excess, and they bond with Na^+ ions to form sodium hydroxide (NaOH), a strong base
- Question #b9441 - Socratic
Catalytic hydrogenation of the ketone "CH"_3"C (=O)CH"_2"CH"_2"CH"_3 stackrelcolor (blue) ("H"_2" Ni"color (white) (mm)) (→) underbrace ("CH"_3"CH (OH)CH"_2"CH"_2"CH"_3)_color (red) ("pentan-2-ol") Step 3
- Question #37fe0 - Socratic
Ethanol to chloroethane underbrace ("CH"_3"CH"_2"OH")_color (red) ("ethanol") stackrelcolor (blue) ("SOCl"_2, "Py"color (white) (mm)) (→) underbrace ("CH"_3"CH"_2"Cl")_color (red) ("chloroethane") Step 2
- Answers created by Paul - Socratic
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- Question #53967 - Socratic
a HI (aq) rarr H^ (+) + I^- b HNO_3 (aq) rarr H^ (+) + NO_3^- c Ba (OH)_2 (aq) rarr Ba^ (2+) + 2HO^- "Hydrogen iodide" is in fact a very strong acid; as is "nitric acid", HNO_3 (in fact the former is a stronger acid than the latter!)
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