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  • Solve f (x)=x^n | Microsoft Math Solver
    The intuition is that for x \in (0,1), x^n converges to 0: higher and higher powers of x get smaller and smaller, and eventually less than any \epsilon > 0 But if x is very close to 1, Fourier Series for f(x)=x^4 when x \in (-\pi, \pi) [closed]
  • Graph f(x)=x^n | Mathway
    Free math problem solver answers your algebra, geometry, trigonometry, calculus, and statistics homework questions with step-by-step explanations, just like a math tutor


















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