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  • operators - What is the difference between || and or in Perl . . .
    53 From Perl documentation: OR List operators On the right side of a list operator, it has very low precedence, such that it controls all comma-separated expressions found there
  • Whats the use of lt; gt; in Perl? - Stack Overflow
    @pst, <> is not a file handle, "null" or otherwise It's an operator Specifically, the readline operator There's a reference to it as the "angle operator" in perlvar, although there isn't actually any such operator The angle brackets are used by two operators: readline or glob The operator depends on the contents of the brackets
  • What does the - gt; arrow do in Perl? - Stack Overflow
    7 Perl arrow operator has one other use: Class−>method invokes subroutine method in package Class though it's completely different than your code sample Only including it for completeness for the question in the title
  • Perl flags -pe, -pi, -p, -w, -d, -i, -t? - Stack Overflow
    Below are the flags that I encounter most often, and I don't have a clue what they mean: perl -pe perl -pi perl -p perl -w perl -d perl -i perl -t I will be very grateful if you tell me what each of those mean and some use cases for them, or at least tell me a way of finding out their meaning
  • How does double arrow (= gt;) operator work in Perl? - Stack Overflow
    The => operator in perl is basically the same as comma The only difference is that if there's an unquoted word on the left, it's treated like a quoted word So you could have written Martin => 28 which would be the same as 'Martin', 28 You can make a hash from any even-length list, which is all you're doing in your example Your Readonly example is taking advantage of Perl's flexibility with
  • How can I parse command-line arguments in a Perl program?
    I'm working on a Perl script How can I parse command line parameters given to it? Example: script pl "string1" "string2"
  • regex - What is ^ and i in Perl? - Stack Overflow
    The match operator is the syntax that tells the Perl interpreter: here comes a regex In Perl, the match operator is normally delimited by ' ' at start and end, but you can use delimiters (e g , m{^foo})
  • How do I perform a Perl substitution on a string while keeping the . . .
    In Perl, what is a good way to perform a replacement on a string using a regular expression and store the value in a different variable, without changing the original? I usually just copy the string to a new variable then bind it to the s regex that does the replacement on the new string, but I was wondering if there is a better way to do this?


















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