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- How can I tell whether or not a molecule is planar?
the molecule will not be planar if there is an $\ce{sp^3}$ hybridized carbon (or nitrogen) atom or two $\ce{sp^2}$ hybridized atoms of carbon nitrogen which are separated by an even number of double bonds and no single bonds Otherwise, its structure allows it to be planar
- organic chemistry - How to determine what compounds are planar . . .
Cyclopropane b always is planar, because you need (at least) three points to define a plane Cyclobutane c is folded slightly, since there is a little room to noticeable wiggle one of the carbons while constraining the other three (careful if you build a model with a model kit like this one-- you can actually break the struts inside "the atoms"
- Why is the crystal field splitting energy larger for square planar than . . .
It is because of the fact that square planar complexes are formed by much strong ligands with d8-metal cation of 3d- series transition metals cation and 4d or 5d-series transition metal cation with either weak or strong ligands The very strong ligands and 4d or 5d-series transition metal cations are responsible for higher crystal field splitting
- Difference between radial, planar, angular and spherical nodes
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- inorganic chemistry - Why is dinitrogen tetroxide a planar molecule . . .
The planar conformation minimizes these interactions Conjugation The conjugation exhibited in the molecule lends to resonance -> electron delocalization Torsional strain As mentioned above, there is a torsional strain at N-N in the planar structure
- Why is [PdCl4]2- square planar whereas [NiCl4]2- is tetrahedral?
If $\Delta E > P + S$, then the complex will be square planar; If $\Delta E < P + S$, then the complex will be tetrahedral This is analogous to deciding whether an octahedral complex adopts a high- or low-spin configuration; where the crystal field splitting parameter $\Delta_\mathrm{O}$, also called $10~\mathrm{Dq}$ in older literature, plays
- inorganic chemistry - How to use crystal field theory to predict . . .
Square planar complexes have a four-tiered diagram (i e four different sets of orbitals with different energies) If it has a two-tiered crystal field splitting diagram then it is tetrahedral But this assumes you have the crystal field splitting diagram of the complex
- Cyclopentadiene planar - Chemistry Stack Exchange
$\begingroup$ Quoting from the given reference "Cyclopentadiene has a planar ring" That is not the same as "Cyclopentadiene is planar" - it means the 5 carbon atoms are all in a plane, not the whole molecule Also note that is an old paper which uses quite primitive methodology by the standards of today $\endgroup$ –
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