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- Mathematics Stack Exchange
Q A for people studying math at any level and professionals in related fields
- How do I square a logarithm? - Mathematics Stack Exchange
$\log_2 (3) \approx 1 58496$ as you can easily verify $ (\log_2 (3))^2 \approx (1 58496)^2 \approx 2 51211$ $2 \log_2 (3) \approx 2 \cdot 1 58496 \approx 3 16992$ $2^ {\log_2 (3)} = 3$ Do any of those appear to be equal? (Whenever you are wondering whether some general algebraic relationship holds, it's a good idea to first try some simple numerical examples to see if it is even possible
- Legendres three-square theorem - Mathematics Stack Exchange
Legendre's three-square theorem Ask Question Asked 5 years, 2 months ago Modified 1 year, 7 months ago
- What does the small number on top of the square root symbol mean?
I just came across this annotation in my school's maths compendium: The compendium is very brief and doesn't explain what this means
- Why cant you square both sides of an equation?
That's because the $9$ on the right hand side could have come from squaring a $3$ or from squaring a $-3$ So, when you square both sides of an equation, you can get extraneous answers because you are losing the negative sign That is, you don't know which one of the two square roots of the right hand side was there before you squared it
- What is $\sqrt {i}$? - Mathematics Stack Exchange
The square root of i is (1 + i) sqrt (2) [Try it out my multiplying it by itself ] It has no special notation beyond other complex numbers; in my discipline, at least, it comes up about half as often as the square root of 2 does --- that is, it isn't rare, but it arises only because of our prejudice for things which can be expressed using small integers
- Why sqrt(4) isnt equall to-2? - Mathematics Stack Exchange
If you want the negative square root, that would be $-\sqrt {4} = -2$ Both $-2$ and $2$ are square roots of $4$, but the notation $\sqrt {4}$ corresponds to only the positive square root
- algebra precalculus - How to square both the sides of an equation . . .
I understand that you can't really square on both the sides like I did in the first step, however, if this is not the way to do it, then how can you really solve an equation like this one (in which there's a square root on the LHS) without substitution?
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