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- How to calculate voltage drop over and power loss in wires
Now, we want to know what the voltage drop over one piece of wire is using \$\text{V}=\text{I}\cdot{}\text{R}\$: \$\text{V}=0 01961\cdot2 5=0 049025V=49 025\text{mV}\$ We can also calculate the voltage over \$\text{R}_{\text{load}}\$ in the same way: \$\text{V}=0 01961\cdot250=4 9025\text{V}\$ Anticipating on voltage loss
- Why does reactive power affect voltage? - Electrical Engineering Stack . . .
This current crosses 0 at the peak of the voltage, so you might say it shouldn't effect the voltage peak However, the current is negative right before the voltage peak This can actually cause a little higher apparent (after the voltage drop on the series resistance) voltage peak immediately before the open-circuit voltage peak
- Why does a resistor reduce voltage if V=IR? [duplicate]
\$\begingroup\$ Yes, the simplest situation is when R is constant and I and V are the variables Of course you could also consider a potentiometer driven by a constant voltage or current source, or a LDR, or a thermistor if you want to think about situations with variable resistors --- but those all vary in response to an external stimulus, not to the applied voltage
- Do MOSFETs have voltage drop across source and drain when turned on?
If you don't give it enough gate voltage (many MOSFETs are specified at 10V, some at 4 5, and fewer at 1 8 or 2 5) you may get a much higher Rds(on) BJT: Voltage drop from collector to emitter is dependent on current but not linearly At low current and with high base current, the BJT might have a voltage drop of tens of millivolts
- How much voltage current is dangerous?
Likewise, if the current and voltage are below a certain level, a person can--given enough time--safely absorb an arbitrarily large amount of electrical energy Further, if voltage is sufficiently low, the amount of current that can flow as a consequence of such voltage will be too low to cause harm \$\endgroup\$ –
- induction - How does the inductor really induce voltage . . .
That voltage is opposed to the externally applied voltage, so there is initially only a small voltage drop across the external resistor, even though the voltage source applied a pulse of +5V That is, the back-EMF voltage of the winding is initially almost 5V also, because the flux is increasing rapidly initially (highest di dt value)
- Why are voltage and current inversely proportional to power, but . . .
Power = voltage (joules charge) * current (charges second) Canceling charges in voltage and current, power comes out in joules second So, for example, if a source provides a power of 10 watts, i e , 10 joules second, and you are using 20 volts, i e , 20 joules charge, then to get 20 joules, it will take 2 seconds, so eventually the speed of
- What is the difference between reverse stand off voltage and . . .
V RWM is the Reverse Working Voltage, the voltage a curcuit works with (e g 3 3 V or 5 V for microcontrollers) At this voltage, the TVS diode should have no effect on the circuit V BR is the Breakdown Voltage at which it starts conducting higher currents This voltage should be higher than the maximum voltage which the power supply would
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