安裝中文字典英文字典辭典工具!
安裝中文字典英文字典辭典工具!
|
- What is the second derivative of f(x)= ln sqrt(x)? | Socratic
To differentiate this and find the second derivative, use the power rule, recalling that #"1 "x=x^-1#
- How do you find the derivative of #f (x)=2 root3 (x)+3cosx#? - Socratic
-2 (3root (3)x^4)-3sinx First, we can write those square root other roots into a simple form x^n Then we can apply the power rule: y=x^n dy dx=y'=nx^ (n-1) Let's start to solve it! f (x)=2 root (3)x+3cosx =2x^ (-1 3)+3cosx f' (x)=2 (-1 3)x^ (-1 3-1)+3 (-sinx) =-2 3x^ (-4 3)-3sinx =-2 (3root (3)x^4)-3sinx Here is the answer Hope it can help you :) Feel free to ask me if you have any questions
- In the set of real numbers, what is the domain of f (x)=sqrt . . . - Socratic
The domain, or allowed values of x, is x>=-5 In interval notation, the domain is [-5,oo) For real numbers, the expression under the square root must be greater than or equal to zero
- Question #3b716 - Socratic
I assume that the poster meant: y=e^x tan sqrt {5x} By rewriting the square-root as the 1 2-power, y=e^xtan (5x)^ {1 2} Let us now find the derivative
- If x = y - 1 y and y gt; 0, simplify, in terms of y: x + square root(x^2 . . .
#x+sqrt (x^2+4)=color (red) (2y)color (white) ("xxxxxx")# or at least that's what I got
- What times the square root of 2 equals 30? - Socratic
15sqrt2 >"let x be the multiplier we require to find" rArrx xxsqrt2=30 rArrx=30 sqrt2 color (blue)"rationalise "" the denominator by multiplying both" "the numerator and denominator by "sqrt2 "this means eliminating the radical from the denominator" [sqrtaxxsqrta=a]larrcolor (blue)"note" rArr (30) sqrt2xxsqrt2 sqrt2 = (30sqrt2) 2=15sqrt2
- 302 Moved
302 Moved The document has moved here
- How do you solve #\sqrt { 19- x } = x + 1#? - x + 1? | Socratic
Square both sides (sqrt (19 - x))^2 = (x + 1)^2 19 - x = x^2 + 2x + 1 0 = x^2 + 3x - 18 0 = (x + 6) (x - 3) x = -6 and 3 However, x= -6 is extraneous since it does not satisfy the original equation Hopefully this helps!
|
|
|