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- c - Is the %zu specifier required for printf? - Stack Overflow
If size_t exists shouldn't zu also be available in printf? size_t existed at least since C89 but the respective format specifier %zu (specifically the length modifier z) was added to the standard only since C99 So, if you can't use C99 (or C11) and had to print size_t in C89, you just have to fallback to other existing types, such as:
- Correct printf format specifier for size_t: %zu or %Iu?
MS Visual Studio didn't support %zu printf specifier before VS2013 Starting from VS2015 (e g _MSC_VER >= 1900) %zu is available As an alternative, for previous versions of Visual Studio if you are printing small values (like number of elements from std containers) you can simply cast to an int and use %d:
- printf - Difference between %zu and %lu in C - Stack Overflow
What is the difference between %zu and %lu in string formatting in C? %lu is used for unsigned long values and %zu is used for size_t values, but in practice, size_t is just an unsigned long CppCheck complains about it, but both work for both types in my experience
- How to get MinGW GCC to recognize the %zu format specifier for size_t?
Imperfection being the name of the game, there may not be a perfect solution I have to believe that, in 2021, Microsoft's C run-time library does support %zu But if the latest version of gcc built into MinGW hasn't caught up to this fact, if it is still warning that the z modifier is unsupported, there may not be much you can do You can send
- c - How to use zd specifier with `printf ()`? - Stack Overflow
But there's really no good reason to do that, since "%zu" is also correct and well defined, without resorting to additional language rules And "%zu" works for all values of type size_t, including those outside the range of the corresponding signed type Finally, POSIX defines a type ssize_t in the headers <unistd h> and <sys types h>
- Is using %zu correct syntax in a printf format string as shown in some . . .
Yes that syntax is correct (at least for C99) Looks like your compiler isn't set up to handle it though Just take out the z and you'll probably be
- Java - Convert integer to string - Stack Overflow
There is absolutely no reason to do any of this You're attempting to shave off each digit from the integer backwards, convert each digit to a character manually, append each digit one at a time to the string builder, before reversing the whole thing to get the original ordering back
- c++ - std::string to char* - Stack Overflow
I want to convert a std::string into a char* or char[] data type std::string str = "string"; char* chr = str; Results in: “error: cannot convert ‘std::string
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