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- What is the formula for Magnesium Triiodine? I think it is Mg(I3)2 but . . .
The correct answer is MgI_2 The correct name of this compound is magnesium iodide Magnesium has +2 and +1 oxidation states , with the +2 being the most common Let us see how we got the answer; Look at the electronic arrangement of Mg and I atoms Mg ( Z= 12) has 12 electrons with following electronic configuration 1s^22s^22p^63s^2 It loses two electron in its 3s subshell to achieve
- In an aqueous solution containing 1. 0 M NH_4Cl (K_a . . . - Socratic
It is complete? the solubility of Mg(OH)_2 is 0,014 g L that divided for its MM =58g mol give a molar solubility of 2,4 xx 10^-4 (mol) L its ionic dissociation give Mg(OH)_2 = Mg^2+ +2OH^- hence the amount of OH^- will be 4,8 xx 10^-4 (mol) L the costant of dissociation of Mg(OH)_2 is: K_S=[Mg^(2+)] xx [OH^-]^2= 5,5 xx 10^(-11) As Mg(OH)_2 is a base weaker of ammonia it doesn't react with NH
- Question #da59d - Socratic
The answer is 1 8 * 10^(-7) "M" The general reaction looks like this Mg_((aq))^(2+) + 2NaOH_((aq)) -> Mg(OH)_(2(s)) + 2Na^(+)(aq) The reaction that is of interest is actually this Mg(OH)2(s) rightleftharpoons Mg_((aq))^(2+) + 2OH_((aq))^(-) In order to determine the maximum concentration of Mg^(2+) ions permissible in the NaOH solution before a precipitate will be formed, you'd need the value
- How does magnesium chemically react with sulfur and oxygen?
Magnesium is a Group 2 metal and thus it has 2 valence electrons, which it commonly loses to give Mg^(2+) when it forms an ionic compound On the other hand, sulfur, and oxygen, non-metal chalcogens, have 6 valence electrons as Group 16 elements, and to achieve a stable Inert gas configuration they are reduced to form O^(2-), or S^(2-)
- Question #ab157 - Socratic
["Mg"^(2+)] = 2 0 * 10^(-3)"M" The clue to what actually happens here lies with the molar solubility and pH of a magnesium hydroxide solution dissolved in pure water As you know, magnesium hydroxide, "Mg"("OH")_2, will not dissociate completely to form magnesium cations, "Mg"^(2+), and hydroxide anions, "OH"^(-) Instead, an equilibrium will be established between the undissolved salt and the
- How do I prepare 1 L of 2 mol L phenylmagnesium bromide?
#"2 mol PhMgBr" × "1 mol Mg" "1 mol PhMgBr" × "24 30 g Mg" "1 mol Mg" = "50 g Mg"# 1 or 2 crystals of I₂ Enough dry THF to make 1 L Note: The I₂ acts as a catalyst for the reaction You often use a large excess of Mg, up to 2 or 3 times the theoretical amount
- Site Map - Mole Ratios Questions and Videos - Socratic
Given the equation, #CH_4 + 2O_2->2H_2O + CO_2#, what is the total number of moles of oxygen that must react to produce 5 moles of carbon dioxide? In the reaction #2Mg + O_2 -> 2MgO#, the law of definite proportions states that for every 2 moles of #Mg# you will need how many moles of #O_2#? Question #99eac
- What is the mass of 4. 18 equiv Mg(OH)2 in a complete . . . - Socratic
In neutralisation reaction of #"Mg(OH)"_2# n-factor is #2#, because it gives #"2 OH"^-# ions #"Mass = Equivalent mass × 2 = 4 18 g × 2 = 8 36 g"# Answer link
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