A bulb of 40 W is producing a light of wavelength 620 nm with . . . A bulb of 40 W is producing a light of wavelength 620 nm with `80%` of efficiency , then the number of photons emitted by the bulb in 20 seconds are : (`1eV = 1 6 xx 10^(-19) J , hc = 12400 eV`) A `2xx10^(18)` B `10^(18)` C `10^(21)` D `2xx10^(21)`
A bulb of 40 W is producing a light of wavelength 620 nm with To solve the problem, we need to calculate the number of photons emitted by a 40 W bulb producing light of wavelength 620 nm with 80% efficiency over a period of 20 seconds Here’s a step-by-step breakdown of the solution: Step 1: Calculate the total energy produced by the bulb in 20 seconds
Bulb of \\ [ { {40W}}\\] is producing a light of wavelength . . . First, we have to calculate the energy emitted by the \[{{100\% }}\] efficiency bulb by using power formula and then calculate the \[{{80\% }}\] efficiency bulb Power of the bulb can be calculating the ratio of energy produced by bulb and time
4. A bulb of 40 W is producing a light of wavelength620 nm . . . Thus, the number of photons emitted by the bulb in 20 seconds are 2 × 10`21 Still have questions? Answer:2 × 10`21 Explanation:Power of a bulb (P) = 40 W (Given)Wavelength of light (λ) = 620 nm (Given)Efficiency = 80% (Given)Energy emitted by a bulb = Power…
Solved: A bulb of 40 W is producing a light of wavelength 620 . . . A bulb of 40 W is producing a light of wavelength 620 nm with 80% efficiency Find the number of photons emitted by the bulb in 20 seconds 1 eV = 1 6 × 10⁻¹⁹ J, hc = 12423 eV Å A 2 × 10¹⁹ B 4 × 10¹⁰ C 5 × 10¹⁰ D 2 × 10¹⁰
(1) A bulb of 40 W is producing a light of wavelength 620 nm . . . (1) A bulb of 40 W is producing a light of wavelength 620 nm with 80% efficiency Then the number of photons emitted in 20 seconds are (1eV = 1 6 X 10 -19 J, hc = 12400 eV A o ) :- (a) 2 X 10 18 (b) 10 18