javascript - Object spread vs. Object. assign - Stack Overflow The difference is that Object assign changes the object in-place, while the spread operator ( ) creates a brand new object, and this will break object reference equality First, let's see the effect, and then I'll give a real-world example of how important it is to understand this fundamental difference First, let's use Object assign:
How can I merge properties of two JavaScript objects? An Object assign method is part of the ECMAScript 2015 (ES6) standard and does exactly what you need (IE not supported) var clone = Object assign({}, obj); The Object assign() method is used to copy the values of all enumerable own properties from one or more source objects to a target object Read more The polyfill to support older browsers:
javascript - When is it necessary to use the Object. assign() method to . . . Object Assign makes a new COPY of the left shoe, including all enumerable OWN properties When you use leftshoe = rightshoe, you are making a REFERENCE to the left shoe A reference points to the same object, not a NEW COPY Thus changing a property of the reference is actually changing the original, as you noted
How do I correctly clone a JavaScript object? - Stack Overflow An Object assign method is part of the ECMAScript 2015 (ES6) standard and does exactly what you need var clone = Object assign({}, obj); The Object assign() method is used to copy the values of all enumerable own properties from one or more source objects to a target object Read more The polyfill to support older browsers:
javascript - What is difference between creating object using Object . . . Object create defines properties and Object assign only assigns them When creating a property, assignments will create it as configurable, writable and enumerable When defining a property, you can specify those flags, but by default it's not configurable, nor writable and not enumerable
javascript - Difference between Object. assign and just assign - Stack . . . const d = Object assign(a, { a: 2 }) console log(a) { a: 2 } console log(b) { a: 2 } console log(d) { a: 2 } Basically, it's important to know that Object assign will mutate the target object as well all variables pointing to it Now, if you use directly the assignment to d, it'll not change the value in a(and in b as well will not