Question #e9fb6 - Socratic x=5 8 Given:" "sqrt (2x+1) sqrt (2x-1)=3 Square both sides giving: (2x+1) (2x-1)=9 Multiply both sides by (2x+1) 2x+1=9 (2x-1) 2x+1=18x-9 Subtract 2x from both sides 1=16x-9 Add 9 to both sides 10=16x Divide both sides by 16 10 16=x Write as: x=10 16 -= (10-:2) (16-:2) = 5 8
Question #e11dd + Example - Socratic 11 8, 22 16, 33 24, 55 40 Not entirely sure what you are asking I’m assuming you want the answer in different denominators (?) So lets solve 5 8+6 8 first (5+6) 8=11 8 We can multiply the answer by 2 2 (as an example) if you want an equivalent fraction We can do this because 2 2=1, so multiplying by 2 2, does not change the value (11 8)*2 2 = 22 16 larr Equivalent fraction You can do
Question #6a28a - Socratic Multiply #1 4# by 1 but where #1=2 2# This does not change the inherent value but it does change the way #1 4# looks So #color (brown) ( (1 4xx1)+3 8)color (blue) (" "->" " (1 4xx2 2)+3 8)# but # (1 4xx2 2)+3 8" is the same as "2 8+3 8# #=5 8# Answer link You can reuse this answer
Question #9ae03 - Socratic 5 8 (root5 (y^4-8))^8+C We will use the Substitution : root5 (y^4-8)=x rArr (y^4-8)=x^5 rArr d (y^4-8)=d (x^5), i e , 4y^3dy=5x^4dx "Therefore, "I=int (root5 (y^4
Question #4c0f4 - Socratic 5 8 Let the fraction be p q Then, (p+q) (q-p)=13 3 So, ((p+q)+(q-p)) ((p+q)-(q-p))=(13+3) (13-3) Eimplifying, q p=16 10 , and the lower form of p q=5 8 satisfies