Semicircle vs hemisphere - English Language Learners Stack Exchange The basic answer is because a language is what it is, and not what somebody thinks it ought to be But historically, the Oxford English Dictionary has semicircle - cited from 1526 hemicircle obsolete or archaic - cited from 1603 semisphere now rare - cited from 1659 hemisphere - cited from 1585 So the standard forms are older, and the OED derives them respectively from Latin sēmicirculus and
What will be the flux due to a point charge on a the flat and curved . . . One more note on the flux through the flat and the curved surface If we look at the geometry of the problem, for $\delta \gt 0$, all the flux from the charge must enter the semisphere through the flat surface, and exit it through the curved surface (simply because electric field lines of an isolated point charge don't bend)
Moment of Inertia of a solid hemisphere. What am I doing wrong? I want to calculate the MOI of a uniform solid hemisphere about Axis passing through its centre of mass (COM) and perpendicular to the circular base Axis coinciding with any diameter at the circ
Drag coefficient of a hemisphere - Physics Stack Exchange I am looking for the aerodynamic drag coefficient of a hemisphere that is set up to flow as follows: In the literature, I only found coefficients for the hemisphere placed in a different setting
integration - Why we consider varying height of element in calculating . . . The 'varying height' R d (theta) in the case of a thin shell, is the width of the ring element, to be multiplied by circumference (2* pi * R * cos (theta)) and by the thickness of the shell (a constant) to make a volume The height of the solid disk-like element of the solid hemisphere is not the slant height of its edge (R d (theta)) but rather the perpendicular-to-the-face height R cos
Method of image charges (semisphere on a metal) I'm currently trying to study ahead for the upcoming semester since I'm on break and I'm stuck on the method of image charges I've tried watching some youtube videos on that topic and I thought I
Tension on a massless string holding a semisphere in place My intuition tells me that, if the semisphere is on a sliding surface, the whole body will rotate in the sense that gets the center of mass lower (to the right, in this case) until the torque becomes at equilibrium with the tension of the rope, but I am not sure how to get there analytically
Electric flux through hemisphere - Physics Stack Exchange My teacher posed this question and it got me thinking; The electric flux through the curved surface area of a hemisphere of radius R when it is placed in a uniform electric field is? Before this,