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Why is $111111111 \times 111111111 = 12345678987654321$
I was looking around on the internet until I stumbled upon this equation $$111111111\\times111111111 = 12345678987654321$$ How does this actually work? It is quite amazing how the number ascend and
sequences and series - Is . . . - Mathematics Stack Exchange
Also, splitting $5\times 11$ the other way around, you get that 11111111111 is also a factor, and it doesn't share any factor with 11111, so this way, you can divide out both of them (if you wanted to get closer to full factorization instead of just proving it's composite) The remaining number is still large, though
The sequence 1,11,111,. . . and the prime factorization of its elements
I have been recently investigating the sequence 1,11,111, I found, contrary to my initial preconception, that the elements of the sequence can have a very interesting multiplicative structure T
When is the number $11111\\cdots1$ a prime number?
For which $n$ is the sum: $$\\sum_{k=0}^{n}10^k$$ a prime number? Are they finite?
The sequence of integers $1, 11, 111, 1111, \ldots$ have two elements . . .
Prove that the sequence $\ {1, 11, 111, 1111, \ldots\}$ will contain two numbers whose difference is a multiple of $2017$ I have been computing some of the immediate multiples of $2017$ to see how
$S= 2^ {1} + 22^ {11} + 222^ {111} \cdots +22222222222^ {11111111111 . . .
The comment about the number of $2's$ and the number of $1's$ is hard to follow In that last summand there are eleven $2's$ and eleven $1's$ So what did you mean?
sequences and series - Mathematics Stack Exchange
Suppose I need to guess a password of one digit Each time I'm wrong the password increases by another digit What's the probability that I can correctly guess the password (assuming I have unlimited
Prove that every number ending in a $3$ has a multiple which consists . . .
Prove that every number ending in a $3$ has a multiple which consists only of ones Eg $3$ has $111$, $13$ has $111111$ Also, is their any direct way (without repetitive multiplication and
Primes dividing $11, 111, 1111, - Mathematics Stack Exchange
How can I prove that every prime except 2 and 5 divide infinitely many of the following integers $11, 111, 1111, $ ?
How to find a formula for the sum up to $n$ terms of the sum $1+11+111 . . .
@S C B I'm trying to find the formula for the sum up to $n$ terms, I'll edit the question title

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