c++ - Is it possible to declare two variables of different types in a . . . See "Is there a way to define variables of two types in for loop?" for another way involving nesting multiple for loops The advantage of the other way over Georg's "struct trick" is that it (1) allows you to have a mixture of static and non-static local variables and (2) it allows you to have non-copyable variables The downside is that it is far less readable and may be less efficient
c++ - Creating a vector that holds two different data types or classes . . . 3 No, a vector must only hold variables of the type declared within the angle brackets < > You could create a class that has an int member and a string member, and then create a vector to hold instances of that class, and then reference the int or string members when you need to
c++ - How do I get the type of a variable? - Stack Overflow The main difference between C++ and Javascript is that C++ is a static-typed language, wile javascript is dynamic In dynamic typed languages a variable can contain whatever thing, and its type is given by the value it holds, moment by moment In static typed languages the type of a variable is declared, and cannot change There can be dynamic dispatch and object composition and subtyping
How to store different data types in one list? (C++) I need to store a list of various properties of an object Property consists of a name and data, which can be of any datatype I know I can make a class "Property", and extend it with different
Is it possible to print (the name of) a variables type in standard C++? 841 C++11 update to a very old question: Print variable type in C++ There are C++14, 17 below as well The accepted (and good) answer is to use typeid(a) name(), where a is a variable name Now in C++11 we have decltype(x), which can turn an expression into a type And decltype() comes with its own set of very interesting rules
c++ - What exactly is std::atomic? - Stack Overflow Objects of atomic types are the only C++ objects that are free from data races; that is, if one thread writes to an atomic object while another thread reads from it, the behavior is well-defined In addition, accesses to atomic objects may establish inter-thread synchronization and order non-atomic memory accesses as specified by std::memory_order
What are primitive types default-initialized to in C++? You are not correct The object is not default-initialized but value-initialized And its value is well-defined int = 0, bool = false, float = 0 0f, enum = (enum type)0, pointer = null pointer pointer to member = null member pointer Note that zero is in the range of values for any enumeration, even if it doesn't contain an explicit enumerator with that vaue, so it's safe to initialize an
How do you constrain a template to only accept certain types An interface in C++ would merely be an abstract class, that is, a class that implements nothing but pure virtual methods Using this method, you could easily implement your java example in C++, without any Concepts or template specializations