geometry - How to find the parametric equation of a cycloid . . . 26 "A cycloid is the curve traced by a point on the rim of a circular wheel as the wheel rolls along a straight line " - Wikipedia In many calculus books I have, the cycloid, in parametric form, is used in examples to find arc length of parametric equations This is the parametric equation for the cycloid:
calculus - Surface area by the revolution of cycloid - Mathematics . . . How to find the surface area of the solid generated by the revolution of the cycloid about $x$-axis? I know the formula to find out the surface area but I'm getting the point that in the formula why we take the integration limit as 0 to $2\pi$
Brachistochrone - Solution of a Cycloid - Parametric Equations I know how to derive the parametric equation of a cycloid, I learnt it from Math Stackexchange|How to find the parametric equation of a cycloid? I just don't know how to solve $ (1)$ using the two equations in $ (2)$
Using Greens theorem to compute an area of a region I like this answer because it clears my confusion of how the curl came into the equation Everyone assumes that everyone knows already The other mystery is that it lets you know the intention of the problem Line integrals are for finding work done It just so happens area and work can be the same thing So in this case you are using the theorem to calculate an area under a curve and this
Finding the area under the cycloid $x=t-\\sin (t),\\;y=1-cos (t)$ C C is curve around D D Let's find form of C C: there are two parts: segment and cycloid Now we should find two points where cycloid touch y y axis, that means solution of: y = 0= 1−cos(t) y = 0 = 1 cos (t) so t = 0 t = 0 and t = 2π t = 2 π Putting value of t t into second equation we have: x= t−sint = 0− 0= 0 x = t sin t = 0 0 = 0
Finding the equation for a (inverted) cycloid given two points If I have two points on a Cartesian plane, and I know that they are connected by a cycloid, then how do I find the equation for that cycloid? For background information, I have been playing around