Get mathematica to simplify expression with another equation I have a very complicated mathematica expression that I'd like to simplify by using a new, possibly dimensionless parameter An example of my expression is: K=a*b*t ((t+f)c*d); (the actual expression is monstrously large, thousands of characters) I'd like to replace all occurrences of the expression t (t+f) with p p=t (t+f);
syntax - What does # mean in Mathematica? - Stack Overflow That means Mathematica doesn't know how to caculate a symbolic result It's just the first root of the polynomial But it does know what is its numerical value: In[7]:= N@Root[-1 - 2 #1 - #1^2 + 2 #1^3 + #1^4 , 1] Out[7]= -2 13224 So, Root[f,k] is a kind of stenographic writing for roots of polynomials with order > 3 I save you from an
Mathematica Module versus With or Block - Stack Overflow Leonid wrote in chapter iv of his book : " Module, Block and With These constructs are explained in detail in Mathematica Book and Mathematica Help, so I will say just a few words about them here " From what I have read ( been able to find ) I am still in the dark
Proper way to simplify integral result in Mathematica given integer . . . Case q = 0: This is a special case that Mathematica misses in the general result, as it implies a constant integrand (I'll often miss it, also, when doing this by hand, so Mathematica isn't entirely to blame ) So, the integral is 2, in this case Strictly speaking, this isn't true
Schrodingers Equation in Mathematica - Stack Overflow I was wondering if there was any way to have mathematica find the solution to Schrodinger's equation [(−h^2 2m)(d^2ψ dx^2) + kx^2ψ=Eψ] for a particle centered at the origin I keep getting a Tag Plus