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relativistic    音標拼音: [r,ɛlətɪv'ɪstɪk]
a. 相對論的

相對論的

relativistic
adj 1: relating or subject to the special or the general theory
of relativity; "relativistic quantum mechanics";
"relativistic increase in mass"; "radiation from
relativistic particles"
2: of or relating to the philosophical doctrine of relativism

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英文字典中文字典相關資料:
  • What is relativistic mass and why it is not used much? - Physics Forums
    It happens that the term relativistic mass is used, in particular in the introductory text on special relativity It should be noted that whether or not to use relativistic mass to a large extent is a matter of convention, convenience, and semantics as long as it is used properly and does not have any impact on the predictions of special
  • Relativistic calculations - when to use them? - Physics Forums
    Essentially, when should I use relativistic calculations (considering gamma in equations like momentum, speed, length, etc )? Homework Equations γ = 1 sqroot(1 - v^2 c^2), and dependent equations The Attempt at a Solution My teacher says that this should only be used for cases where "it makes a difference", and uses "like, 99% of c" as his
  • How Does Newtons Second Law Adapt to Relativistic Speeds? - Physics Forums
    Differentiating the above expression for relativistic momentum will give the correct force acceleration relationships assuming the forces and the accelerations are measured in the laboratory frame Sometimes, accelerations are measured in the frame of the object being accelerated, such as in the relativistic rocket
  • Learn the Relativistic Work-Kinetic Energy Theorem - Physics Forums
    Using the relativistic energy-momentum four-vector A more modern approach is as follows Suppose that we’ve already determined the properties of the energy-momentum four-vector This includes the relativistic definition of mass, ##m^2=E^2-p^2##, and also the identity ##p E=v## Then is becomes pretty straightforward to show that ##W=Fd## is
  • Relativistic electrodynamics: transformation of electric dipole moment
    A charge distribution stationary in its own frame S’ has a static charge density ##\\rho ’##, a total charge of 0 and a net electric dipole ##\\vec{p'}## An observer in frame S sees the charge distribution moving with constant velocity ##\\vec{v}=c \\vec{\\beta}## What is the magnetic dipole moment
  • What is the correct derivation of the relativistic rocket equation?
    The relativistic mass is not a property of the body in and of itself (The invariant mass is - it is the same for all observers) Because the invariant mass does not depend on the frame in which it is measured, it is probably the invariant mass ratio that you want to use, which is the one used in the first set of equations
  • Relativistic Wavelength of Electron in Transmission Electron Microscop
    So, I found a relativistic expression of the electron wavelength online, and it goes like this: [itex] \lambda = \sqrt{\frac{h^2 c^2}{eV \cdot [2m_0c^2 + eV]}} [ itex] I wanted to do a little derivation of this expression I started from the relativistic energy of a particle as described by Einstein in his special relativity: [itex]
  • Relativistic de Broglie Wavelength - Physics Forums
    This is because in non-relativistic case the rest mass is not considered in the Energy term So, if you can find a method for measuring the phase velocity of a particle, it would be another criterion for the validity of relativistic theory
  • Relativistic rotational kinetic energy - Physics Forums
    Kinetic energy is not a particularly useful concept in special relativity Neither is the 'relativistic mass ' Always use the rest mass and put in the factors of γ explicitly The exact formula for the total energy of a particle is E 2 = m 2 c 4 + p 2 c 2 where p = γmv This can be written E = mc 2 √(1 + γ 2 v 2 c 2)
  • Relativistic centripetal force - Physics Forums
    Now I needed the relativistic centripetal force, in Lab-frame (shall measure momenta of relativistic particles tracks in a bubble chamber) All sources I have consulted (wanted to check my derivation), tells me that: [tex] F = \dfrac{\gamma m v^2}{r} = \dfrac{pv}{r} [ tex] Just so you guys might have something more to talk about:)





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