What is 29 degrees celsius in fahrenheit? - Socratic color(blue)("Fahrenheit temperature "=(29xx9 5)+32 = 84 2^o F ) The numbers to remember are 5, 9 and 32 Fahrenheit are the lager number when comparing like temperature for like So to convert Centigrade to Fahrenheit, you need to make the numbers bigger Thus you multiply by 9 5 To go from Fahrenheit to centigrade you are making the numbers smaller so you multiply by 5 9 All you need to
What is the Celsius temperature scale? - Socratic The Celsius scale is a temperature scale in which the freezing and boiling points of water are exactly 0 °C and 100 °C There are 100 equal degrees between these two temperatures These temperatures do not define the Celsius scale International agreement defines the reference points as absolute zero and the triple point temperature of specially purified water The triple point of water is
Question #1b0c9 - Socratic You have "0 239 kg" of ideal gas in your cylinder So, you know the volume your gas occupies, and the temperature and pressure at which it is kept Because you were given its molar mass, you can solve for its mass by using the ideal gas law equation, PV = nRT, to determine how many moles are present in the cylinder SInce you know the weight of 1 mole, determining the number of moles will help
Question #ade0c - Socratic As you know, changes in temperature are identical for temperature expressed in degrees Celsius and for Kelvin, you can say that the calorimeter has a heat capacity of "1 kJ"^@"C"^(-1) Now, heat capacity tells you how much heat must be added or removed from a system in order to cause a 1^@"C" change in its temperature
18g of glucose is added to 178. 2g of water. The vapour . . . - Socratic The water vapour pressure is 91 2 kPa· > This is a Raoult's law problem Raoult's law states that the vapour pressure of a solution of a non-volatile solute is equal to the vapour pressure of the pure solvent at that temperature multiplied by its mole fraction In symbols, p = chi_1p_1^@ where chithe mole fraction of the solvent p and p_1^@ are the vapour pressures of the solution and of the
Question #7af06 - Socratic You are right, this is a job for the ideal gas law equation, which as you know looks like this #color(blue)(|bar(ul(color(white)(a a)PV = nRTcolor(white)(a a)|)))" "#, where
A helium balloon at 28 degrees Celsius has a volume of 1. 8 L . . . - Socratic Note: The temperature for gas laws must be in Kelvins, so the Celsius temperatures will have to be converted Known #P_1="102 kPa"# #V_1="1 8 L"# #T_1="28"^@"C + 273 15"="301 K"# #P_2="85 kPa"# #T_2="4"^@"C + 273 15"="277 K"# Unknown #V_2# Solution Rearrange the equation to isolate #V_2# Plug in the known values and solve #V_2=(P_1V_1T_2
Why do colligative properties depend on the number of particles? Colligative properties are properties of solutions that depend upon the ratio of the number of solute particles to the number of solvent molecules in a solution, and not on the type of chemical species present Colligative properties include: 1 Relative lowering of vapor pressure 2 Elevation of boiling point 3 Depression of freezing point 4 Osmotic pressure For example, the freezing
What is calculus? - Socratic That is, it is the limit of the slope of the line between #(a, f(a))# and #(a+h, f(a+h))# as #h->0# I have only touched the tiniest fragment of what Calculus is about here, but start from the intuition and it may make more sense than going straight for formulas