Question #e8868 | Socratic Discover how Lens in the Google app can help you explore the world around you Use your phone's camera to search what you see in an entirely new way
Question #16a2c - Socratic 3rd term is 20 This is called a geometric sequence, these have the genral nth term foruma of: a_n = a * r^(n-1) Where a - "first term " n = 1 r = "common ration" = a_2 a_1 = a_m a_(m-1) Hence the first term of this is a = 5 and the ratio is 10 5 = 2 So the nth term of this sequance is 5 * 2^(n-1) Applying this formula : a_3 = 5 * 2^2 = color(red)(20 or just looking at the sequence, color
How do you simplify #2 5 + 5 20#? - 5 20? | Socratic 13 20 To add or subtract fractions, they have to have the same denominators We use the small possible common denominator IN this case both 5 and 20 can divide into 20, so this is the LCD Covert to equivalent fractions and then add the numerators 2 5 + 5 20 = (2xx4) (5xx4) + 5 20 = (8+5) 20 = 13 20
How do you solve 117- 11h = 40? | Socratic h = 7 Move the variable to the other side of the equation to make it positive You'd get 117 = 11h + 40 Then move 40 to the other side of the equations, which makes it negative You'd get 77 = 11h Then you simply divide both sides by 11 to get 7 = h
Question #ab157 - Socratic ["Mg"^(2+)] = 2 0 * 10^(-3)"M" The clue to what actually happens here lies with the molar solubility and pH of a magnesium hydroxide solution dissolved in pure water As you know, magnesium hydroxide, "Mg"("OH")_2, will not dissociate completely to form magnesium cations, "Mg"^(2+), and hydroxide anions, "OH"^(-) Instead, an equilibrium will be established between the undissolved salt and the
Question #ffee6 - Socratic First, we need to find the prime numbers between 10 and 20 The numbers between 10 and 20 are: 11, 12, 13, 14, 15, 16, 17, 18, 19 First, we can eliminate the even
Question #82e24 - Socratic You can do this question using simple linear equation Let the number of cans she collected yesterday be x The cans she collected today were ' double the number of cans that she collected yesterday, less 2 cans' i e (2 ⋅ x) −2 But the cans she collected today are 44 Hence, (2 ⋅ x) −2 = 44 ⇒ 2 ⋅ x = 44+ 2 ⇒ 2 ⋅ x = 46 ⇒ x = 46 2 = 23 ∴ x = 23 D is the answer
Question #6558e - Socratic 6 2 * 10^(-4) The idea here is that you can find the equilibrium concentration of atomic bromine, "Br", by using the percent of molecular bromine, "Br"_2, that gets converted by the reaction Once you know the equilibrium concentrations of both chemical species, you can solve for the equilibrium constant of the reaction Calculate the concentration of molecular bromine by using the given