What is the chemical formula for lithium hydroxide? - Socratic Lithium is a Group 1 metal and commonly forms a M + ion Hydroxide anion, −OH, has a unit negative charge When they make music together, there is thus 1:1 stoichiometry between ions: Li(s) + H 2O(l) → LiOH (aq) + 1 2 H 2(g) ↑ ⏐ ⏐⏐
What is the formula of magnesium hydroxide? | Socratic Mg (OH)_2 Now we know that hydroxides are salts of HO^-, and some metal ion Now if the parent metal has an electronic configuration of 2:8:2, then there are 12 electrons, and the atomic number of the metal is equal to 12 We look on the Periodic Table, and we find that Z=12, for "magnesium metal" As a Group 2 metal, magnesium forms a Mg^ (2+) ion, and hence its hydroxide is Mg (OH)_2
What is the value of ΔG°cell? - Socratic ΔG_text (cell)^@= "-332 kJ·mol"^"-1"" Your standard reduction potentials for each half-reaction are: ulbb ("Standard Reduction Potentials"color (white) (mmmmmll)E
Question #6b9a2 - Socratic In order to answer these questions we first need to know the equation representing this chemical reaction In this case, it is a reaction between HCl and Ca (OH)2: Ca (OH) 2 + HCl → CaCl 2 +H 2 O Let's balance the equation: Ca (OH) 2 + 2 HCl → CaCl 2 + 2 H 2 O a Using the formula n = m M: ⇒ n(Ca (OH)) = 0 75 g 74 10 g mol−1 ⇒ n(Ca (OH)) = 0 01 mol In the balanced chemical equation
Why does neutralisation of any strong acid in an aqueous . . . - Socratic Because its the same reaction A monobasic [monoprotic] acid like HCl has one H atom, which fully dissociates to form a hydrogen ion, H^+ The strong alkali fully dissociates to forman hydroxide ion OH^-, which react to from water This is the ionic equation for neutralisation and occurs for all strong acid strong alkali reactions
Molarity question? - Socratic Consider the precipitation reaction of CuCl2 with NaOH: CuCl2 (aq) + 2NaOH (aq) -> Cu (OH)2 (s) + 2NaCl (aq) A What is the theoretical yield (in moles) of copper (II) hydroxide when 100mL of 0 125M CuCl2 is combined with 100 mL of 0 230M NaOH? I got 0 0115 mol Cu (OH)2 B What is the concentration (M) of each anion in solution after the reaction is complete? I got 0 125 M for Cl I know that
Question #bcaa2 + Example - Socratic Or, relative to benzene, the present OH is an electron-donating group, which donates electron density into the aromatic ring, away from the proton That makes the hydroxyl proton more partially positive than in benzene, whose hydrogens are all belonging to the aromatic ring That means it's more acidic, and so phenol is more prone to deprotonation than benzene As a note, the pKa of benzene is
Calculating the concentration of excess HCL in E - Socratic The acid in excess is then titrated with N aOH (aq) of KNOWN concentration we can thus get back to the concentration or molar quantity of M (OH)2 as it stands the question (and answer) are hypothetical