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equidistant

XDict

a. 距離相等的,等距的

PyDict

距離相等的,等距的

WordNet (r) 3.0 (2006) (WordNet)

equidistant
adj 1: the same distance apart at every point

The Collaborative International Dictionary of English v.0.48 (gcide)

Equidistant \E`qui*dis"tant\, a. [L. aequidistans, -antis;
aequus equal distans distant: cf. F. ['e]quidistant.]
Being at an equal distance from the same point or thing. --
{E`qui*dis"tant*ly}, adv. --Sir T. Browne.
[1913 Webster]

Moby Thesaurus II by Grady Ward, 1.0 (moby-thesaurus)

48 Moby Thesaurus words for "equidistant":
aligned, amidships, analogous, average, center, centermost,
central, coextending, coextensive, collateral, concurrent, core,
equal, equatorial, equispaced, even, halfway, interior,
intermediary, intermediate, lined up, mean, medial, median,
mediocre, mediterranean, medium, mesial, mezzo, mid, middle,
middlemost, middling, midland, midmost, midships, midway,
nonconvergent, nondivergent, nuclear, parallel, parallelepipedal,
parallelinervate, paralleling, parallelodrome, parallelogrammatic,
parallelogrammic, parallelotropic

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equidistant	查看　equidistant　在Google字典中的解釋	Google英翻中〔查看〕
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Find the point on the x-axis which is equidistant from points (2,-5 . . .
Answer: The point on the x-axis is (7, 0) which is equidistant from points (2, - 5) and (- 2, 9) Step-by-step explanation: We have to find the point on the x-axis which is equidistant from the points (2,-5) and (-2,9) Let assume that the point on x - axis be P (x, 0) Now, the point on the x-axis P (x, 0) is equidistant from the points A (2,-5) and B (-2,9) So, According to statement, On
P (-2, 5) and Q (2, -1) are two points on the coordinate . . . - Brainly
The given equation represents the locus of points equidistant from P (-2, 5) and Q (2, -1) However, this locus is not a single point, but a line passing through the midpoint (0, 2) which is equidistant from P and Q
ii) iii) The magnetic field in a region is represented by equidistant . . .
**Equidistant parallel magnetic field lines** indicate that the magnetic field is **uniform** in the region A uniform magnetic field means the field strength and direction are the same at every point within the region
p is a point equidistant from two lines l and m intersecting at point A . . .
Then: d_1 = d_2 Step 2: Geometric properties of angle bisectors In geometry, a point equidistant from two intersecting lines lies on the angle bisector of the angle formed by those lines Step 3: Line and the angle bisector Since is equidistant from the lines and , the point must lie on the angle bisector of the angle formed by the lines and
Prove that the chords equidistant from the centre of a circle . . . - Brainly
Answer: To prove that chords equidistant from the center of a circle are equal in length, we can follow these steps: Given: A circle with center Two chords and that are equidistant from the center Let the distance from to both chords be To Prove: Proof: 1 Draw Perpendiculars: Draw perpendiculars from the center to the chords and
P (-2, 5) and Q (2, -1) are two points on the coordinate . . . - Brainly
This is true because the midpoint of two points on a coordinate plane is the unique point equidistant from those two points (R) states that there are many points (x, y) where are equidistant from P and Q
The point on x-axis which is equidistant from the points (5 . . . - Brainly
Answer: The point on x - axis which is equidistant from the points (5, - 3) and (4, 2) is (7, 0) Step-by-step explanation: Let assume that coordinates of a point on x - axis which is equidistant from the points (5, - 3) and (4, 2) be P (x, 0) Let further assume that point (5, - 3) and (4, 2) be denoted as A and B respectively Now, According to statement, On squaring both sides, we get Hence
The (x) coordinate of a point (P) is twice its (y . . . - Brainly
Answer:Let's solve this step by step 1 Define the coordinates of P: Since the x-coordinate of point P is twice its y-coordinate, we can write: P (x, y) = (2…
Find a point on the x-axis which is at equal distance from . . . - Brainly
Answer: The point on the x-axis equidistant from points P and Q is R (2 8, 0, 0) Step-by-step explanation: To find a point on the x-axis equidistant from points P (0,3,2) and Q (5,0,4), we can follow these steps: 1 Let the point on the x-axis be R (x, 0, 0) 2 Calculate the distance between point P and point R 3 Calculate the distance between point Q and point R 4 Equate the distances
find the relation between x And y such that the point (x,y . . . - Brainly
find the relation between x And y such that the point (x,y) is equidistant from the points (7,1) ,( 3,5) - 18387384

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