Why is y=a a horizontal asymptote on the polar coordinates? Hi guys, I was trying to sketch a polar curve but my curve was different from the curve on maple(I plotted the same curve on maple) Homework Statement Here is the whole question, I am using t as theta The hyperbolic spiral is described by the equation rt=a whenever t>0,where a is a
Asymptote of a curve in polar coordinates - Physics Forums I understood the concept behind how this asymptote is calculated, but I am not very fluent in mathematics to convert the above information into a comprehensive proof Moreover, there is another statement that states that I have to make use of the information ## \lim_{\theta \rightarrow 0}x=+\infty##
Oblique Asymptotes: What happens to the Remainder? - Physics Forums An "asymptote" is a line that a curve approaches as x goes to, in this case, negative infinity and infinity Yes, long division gives a quotient of -3x- 3 with a remaider of -1 Yes, long division gives a quotient of -3x- 3 with a remaider of -1
Vertical Asymptote: Is f Defined at x=1? - Physics Forums Homework Statement True False If the line x=1 is a vertical asymptote of y = f(x), then f is not defined at 1 Homework Equations none The Attempt at a Solution I originally believed this was true, but on finding it was false it sought a counter example: if for example f(x) = 1 x if x !=
Determining the horizontal asymptote - Physics Forums My interest is on the horizontal asymptote, now considering the degree of polynomial and leading coefficients, i have ##y=\dfrac{2}{1} =2## Therefore ##y=2## is the horizontal asymptote The part that i do not seem to get is (i already checked this on desmos) why an asymptote can be regarded as such if it is crossing the curve
Describing behavior on each side of a vertical asymptote - Physics Forums Find the vertical asymptotes of the graph of F(x) = (3 - x) (x^2 - 16) ok if i factor the denominator i find the vertical asymptotes to be x = 4, x = -4 The 2nd part of the problem asks: Describe the behavior of f(x) to the left and right of each vertical asymptote I'm not sure