Asymptote of a curve in polar coordinates - Physics Forums I understood the concept behind how this asymptote is calculated, but I am not very fluent in mathematics to convert the above information into a comprehensive proof Moreover, there is another statement that states that I have to make use of the information ## \lim_{\theta \rightarrow 0}x=+\infty##
Why is y=a a horizontal asymptote on the polar coordinates? Hi guys, I was trying to sketch a polar curve but my curve was different from the curve on maple(I plotted the same curve on maple) Homework Statement Here is the whole question, I am using t as theta The hyperbolic spiral is described by the equation rt=a whenever t>0,where a is a
Oblique Asymptotes: What happens to the Remainder? - Physics Forums An "asymptote" is a line that a curve approaches as x goes to, in this case, negative infinity and infinity Yes, long division gives a quotient of -3x- 3 with a remaider of -1 Yes, long division gives a quotient of -3x- 3 with a remaider of -1
Vertical Asymptote: Is f Defined at x=1? - Physics Forums Homework Statement True False If the line x=1 is a vertical asymptote of y = f(x), then f is not defined at 1 Homework Equations none The Attempt at a Solution I originally believed this was true, but on finding it was false it sought a counter example: if for example f(x) = 1 x if x !=
Horizontal asymptotes - approaches from above or below? - Physics Forums I seem to be having a lot of difficulty finding whether for a horizontal asymptote, whether the curve approaches the asymptote from above or below For example, for the problem y = \\frac{6x + 1}{1 - 2x}, I know that: For the vertical asymptote, x = 1 2, and that \\lim_{x \\to
What is an asymptote and how do we find it in graphing ln(x)? Homework Statement the qns is : sketch the graph of y=3ln(x+2) , showing clearing the asymptote and the x-intercept im wondering wat is asymptote and how we find it :confused: Homework Equations The Attempt at a Solution
Do polynomials have asymptotes? - Physics Forums It does depend on exactly what you mean by "asymptote" For example, in some sense, -x³ is an asymptote to 2 - 15x + 9x² - x³ And in some other sense, the vertical line x=0 is an asymptote to x² But let's ignore these other meanings for now! You have a conjecture, and the first thing you need to do is to figure out exactly what you want
Determining the horizontal asymptote - Physics Forums My interest is on the horizontal asymptote, now considering the degree of polynomial and leading coefficients, i have ##y=\dfrac{2}{1} =2## Therefore ##y=2## is the horizontal asymptote The part that i do not seem to get is (i already checked this on desmos) why an asymptote can be regarded as such if it is crossing the curve